document.write( "Question 272867: The perimeter of a rectangle is 38 inches. If the length of the rectangle is three inches more than three times the width, find the dimensions. \n" ); document.write( "

Algebra.Com's Answer #199434 by JBarnum(2146) $\"\"$ $\"About$

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perimeter is $\"P=2L%2B2W\"$ where $\"P=38\"$
\n" ); document.write( "if $\"L=3%2B3W\"$ (length is three morethan three times width)
\n" ); document.write( "then simply use substitution
\n" ); document.write( " $\"P=2L%2B2W\"$
\n" ); document.write( " $\"38=2L%2B2W\"$
\n" ); document.write( " $\"38=2%283%2B3W%29%2B2W\"$ solve for W
\n" ); document.write( " $\"38=6%2B6W%2B2W\"$ add
\n" ); document.write( " $\"38=6%2B8W\"$ subtract
\n" ); document.write( " $\"32=8W\"$ divide
\n" ); document.write( " $\"4=W\"$
\n" ); document.write( "___________
\n" ); document.write( " $\"L=3%2B3W\"$ substitute
\n" ); document.write( " $\"L=3%2B3%284%29\"$ multiply
\n" ); document.write( " $\"L=3%2B12\"$ add
\n" ); document.write( " $\"L=15\"$
\n" ); document.write( "___________
\n" ); document.write( "Check
\n" ); document.write( " $\"P=2L%2B2W\"$ substitute
\n" ); document.write( " $\"38=2%2815%29%2B2%284%29\"$ multiply
\n" ); document.write( " $\"38=30%2B8\"$ add
\n" ); document.write( " $\"38=38\"$
\n" ); document.write( "Correct \n" ); document.write( "

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