document.write( "Question 272736: The perimeter of a rectangle is 40. If its length is 2 more than 5 times its width, find the dimensions of the rectangle.\r
\n" ); document.write( "\n" ); document.write( "My solution is -perimeter =L+W
\n" ); document.write( "since Length is 2 more than 5 times width then length would be (5w+2)
\n" ); document.write( "so I was thinking 40=(2+5w) + w but the answer I get solving for w is 5 which doesn't calculate in my formula as being correct
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Algebra.Com's Answer #199401 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
You need to double each dimension to get \"40=2%282%2B5w%29%2B2w\" since the original perimeter formula is \"P=2L%2B2W\". \n" ); document.write( "
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