document.write( "Question 272631: How many quarts of pure antifreeze must be added to 6 quarts of a 10% solution to obtain a 20% antifreeze soltuion? (Round to the nearest tenth.) \n" ); document.write( "
Algebra.Com's Answer #199373 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
How many quarts of pure antifreeze must be added to 6 quarts of a 10% solution to obtain a 20% antifreeze soltuion? (Round to the nearest tenth.)\r
\n" ); document.write( "\n" ); document.write( "Let the quantity of pure antifreeze added be x\r
\n" ); document.write( "\n" ); document.write( "pure(100%)--------------- 10%------------------------- 20 % mix\r
\n" ); document.write( "\n" ); document.write( "x-------------------------6-------------------------- x+6 quarts\r
\n" ); document.write( "\n" ); document.write( "1x+0.6x=0.2(x+6)\r
\n" ); document.write( "\n" ); document.write( "1.6x= 0.2x + 1.2\r
\n" ); document.write( "\n" ); document.write( "1.6x-0.2x= 1.2\r
\n" ); document.write( "\n" ); document.write( "1.4x= 1.2
\n" ); document.write( "x= 1.2/1.4\r
\n" ); document.write( "\n" ); document.write( "0.85 quarts\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );