document.write( "Question 272564: the length of a rectangle is 5 units longer than its width. The perimeter of this rectangle is 74cm. determine the length and the width of this rectangle. \n" ); document.write( "
Algebra.Com's Answer #199342 by oberobic(2304)![]() ![]() ![]() You can put this solution on YOUR website! L = length \n" ); document.write( "W = width \n" ); document.write( "P = perimeter = 2L + 2W = 2(L + W) \n" ); document.write( ". \n" ); document.write( "L = W+5 \n" ); document.write( "P = 74 \n" ); document.write( ". \n" ); document.write( "2L + 2W = 74 \n" ); document.write( "substituting \n" ); document.write( "2(W+5) + 2W = 74 \n" ); document.write( "2W + 10 + 2W = 74 \n" ); document.write( "4W = 64 \n" ); document.write( "W = 16 \n" ); document.write( ". \n" ); document.write( "L = W+5 = 16+5 = 21 \n" ); document.write( ". \n" ); document.write( "Checking \n" ); document.write( "P = 74 ?? \n" ); document.write( "2(21) + 2(16) = 42 + 32 = 74 \n" ); document.write( "Yes. \n" ); document.write( ". \n" ); document.write( "Answer: \n" ); document.write( "L = 21 \n" ); document.write( "W = 16 \n" ); document.write( ". \n" ); document.write( "Done \n" ); document.write( " |