document.write( "Question 272191: A is 1/4 as old as B.5 years later A will be 1/3 as old as B.How old is A now? \n" ); document.write( "
Algebra.Com's Answer #199323 by ankor@dixie-net.com(22740)\"\" \"About 
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A is 1/4 as old as B.
\n" ); document.write( "A = \"1%2F4\"B
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\n" ); document.write( "5 years later A will be 1/3 as old as B.
\n" ); document.write( "A + 5 = \"1%2F3\"(B+5)
\n" ); document.write( "replace A with \"1%2F4\"B
\n" ); document.write( "\"1%2F4\"B + 5 = \"1%2F3\"(B+5)
\n" ); document.write( "multiply by 12 to get rid of the fractions; results:
\n" ); document.write( "3B + 12(5) = 4(B+5)
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\n" ); document.write( "3B + 60 = 4B + 20
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\n" ); document.write( "60 - 20 = 4B - 3B
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\n" ); document.write( "B = 40 yrs
\n" ); document.write( "then
\n" ); document.write( "A = \"1%2F4\"*40
\n" ); document.write( "A = 10 yrs\r
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