document.write( "Question 272475: a 25 foot wire is to be cut so the longer piece is 1 foot longer than 5 times the shorter piece. find both lengths \n" ); document.write( "
Algebra.Com's Answer #199314 by oberobic(2304) ![]() You can put this solution on YOUR website! The 25-ft wire is cut into two pieces. We can call these 'x' and 'y'. And in algebra, we'd say: \n" ); document.write( "x + y = 25 \n" ); document.write( "or \n" ); document.write( "y = 25-x \n" ); document.write( ". \n" ); document.write( "We also are told there is a relationship between the lengths of 'x' and 'y'. \n" ); document.write( "x = 5y + 1 :: 'x' is 1 foot longer than 5 times 'y' \n" ); document.write( ". \n" ); document.write( "substituting y = 25-x, we have \n" ); document.write( "x = 5(25-x) + 1 \n" ); document.write( ". \n" ); document.write( "multiplying through \n" ); document.write( "x = 125 - 5x + 1 \n" ); document.write( ". \n" ); document.write( "collecting terms \n" ); document.write( "6x = 126 \n" ); document.write( ". \n" ); document.write( "dividing by 6 \n" ); document.write( "x = 126/6 = 21 \n" ); document.write( ". \n" ); document.write( "Since x+y = 25, then \n" ); document.write( "y = 25 - 21 = 4 \n" ); document.write( ". \n" ); document.write( "Checking our work \n" ); document.write( ". \n" ); document.write( "Do they sum to 25? \n" ); document.write( "x + y = ?? \n" ); document.write( "21 + 4 = 25 \n" ); document.write( "Yes \n" ); document.write( ". \n" ); document.write( "Is x = 5*y + 1? \n" ); document.write( "5(4) + 1 = 21 ?? \n" ); document.write( "Yes \n" ); document.write( ". \n" ); document.write( "So our answer is: \n" ); document.write( "x = 21 feet \n" ); document.write( "y = 4 feet \n" ); document.write( ". \n" ); document.write( "Done \n" ); document.write( " |