document.write( "Question 272459: write a quadratic equation with integral coefficients and roots equal to 2/3 and -1/2 \n" ); document.write( "

Algebra.Com's Answer #199305 by oberobic(2304) $\"\"$ $\"About$

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In general, a quadratic equation may be depicted as y = (x + j)(x + k), where j & k are numbers. The roots of the equation will be the value of x that make x+j = 0 and the value of x that makes x+k = 0.
\n" ); document.write( "So, we want the roots to be 2/3 and -1/2, which means:
\n" ); document.write( "y = (x-2/3)(x+1/2)
\n" ); document.write( "Notice the signs are reversed so the roots will be the value indicated.
\n" ); document.write( "Multiplying through, we have
\n" ); document.write( "y = x^2 + 1/2x - 2/3x -2/6
\n" ); document.write( "y = x^2 + 3/6x - 4/6x - 2/6
\n" ); document.write( "y = x^2 - 1/6x - 2/6
\n" ); document.write( ".
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