document.write( "Question 272377: Solving using the substitution method: \r
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document.write( "8x - 5y = -47
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document.write( "4x + 3y = -7\r
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document.write( "I got some help from the site, but I dont know how it derived to that answer. When doing it long hand, I couldn't get the same results.\r
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document.write( "Expressing x as a function of y (from the first equation) x = (-47 +5y)/8
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document.write( "Substituting this expression into the second equation:\r
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document.write( "4(-47-5y)/8+3y = -7\r
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document.write( "Simplifying this expression:\r
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document.write( "44y = 132 or y = 3\r
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document.write( "Now, substituting y = 3 back into the x expressed as a function of y:
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document.write( "x = (-47+5y)/8 = -4
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Algebra.Com's Answer #199269 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! 8x - 5y = -47 \n" ); document.write( "8X=5Y-47 \n" ); document.write( "X=(5Y-47)/8 \n" ); document.write( "4x + 3y = -7 \n" ); document.write( "4(5Y-47)/8+3Y=-7 \n" ); document.write( "(20Y-188)/8+3Y=-7 \n" ); document.write( "(20Y-188+3Y*8)/8=-7 \n" ); document.write( "20Y-188+24Y=-56 \n" ); document.write( "44Y=-56+188 \n" ); document.write( "44Y=132 \n" ); document.write( "Y=132/44 \n" ); document.write( "Y=3 ANS. \n" ); document.write( "X=(5*3-47)/8 \n" ); document.write( "X=(15-47)/8 \n" ); document.write( "X=-32/8 \n" ); document.write( "X=-4 ANS. \n" ); document.write( "PROOF: \n" ); document.write( "4*-4+3*3=-7 \n" ); document.write( "-16+9=-7 \n" ); document.write( "-7=-7 \n" ); document.write( " \n" ); document.write( " |