document.write( "Question 272377: Solving using the substitution method: \r
\n" ); document.write( "\n" ); document.write( "8x - 5y = -47
\n" ); document.write( "4x + 3y = -7\r
\n" ); document.write( "\n" ); document.write( "I got some help from the site, but I dont know how it derived to that answer. When doing it long hand, I couldn't get the same results.\r
\n" ); document.write( "\n" ); document.write( "Expressing x as a function of y (from the first equation) x = (-47 +5y)/8
\n" ); document.write( "Substituting this expression into the second equation:\r
\n" ); document.write( "\n" ); document.write( "4(-47-5y)/8+3y = -7\r
\n" ); document.write( "\n" ); document.write( "Simplifying this expression:\r
\n" ); document.write( "\n" ); document.write( "44y = 132 or y = 3\r
\n" ); document.write( "\n" ); document.write( "Now, substituting y = 3 back into the x expressed as a function of y:
\n" ); document.write( "x = (-47+5y)/8 = -4
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #199269 by checkley77(12844)\"\" \"About 
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8x - 5y = -47
\n" ); document.write( "8X=5Y-47
\n" ); document.write( "X=(5Y-47)/8
\n" ); document.write( "4x + 3y = -7
\n" ); document.write( "4(5Y-47)/8+3Y=-7
\n" ); document.write( "(20Y-188)/8+3Y=-7
\n" ); document.write( "(20Y-188+3Y*8)/8=-7
\n" ); document.write( "20Y-188+24Y=-56
\n" ); document.write( "44Y=-56+188
\n" ); document.write( "44Y=132
\n" ); document.write( "Y=132/44
\n" ); document.write( "Y=3 ANS.
\n" ); document.write( "X=(5*3-47)/8
\n" ); document.write( "X=(15-47)/8
\n" ); document.write( "X=-32/8
\n" ); document.write( "X=-4 ANS.
\n" ); document.write( "PROOF:
\n" ); document.write( "4*-4+3*3=-7
\n" ); document.write( "-16+9=-7
\n" ); document.write( "-7=-7
\n" ); document.write( "
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