document.write( "Question 271386: simplify:
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document.write( "4n/ n squared - 4 minus 2/n + 2 minus 2/n + 2\r
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document.write( "a. 2/n - 2
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document.write( "b. 4n - 2/n squared - n - 6
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document.write( "c. 2/n + 2
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document.write( "d. 1/n - 1
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document.write( "Thanks \n" );
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Algebra.Com's Answer #199192 by jsmallt9(3758)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Since subtractions can a source of errors for many people, I am going to start by changing the subtractions into additions: \n" ); document.write( " \n" ); document.write( "and the last two terms have the same denominator so I will go ahead and add them: \n" ); document.write( " \n" ); document.write( "To add the remaining fractions we need to get a common denominator first. And to find the Lowest Common Denominator (LCD) we need to factor each denominator: \n" ); document.write( " \n" ); document.write( "From this we can see that
\n" ); document.write( "So we will multiply the numerator and denominator of the second fraction by n-2: \n" ); document.write( " \n" ); document.write( "which simplifies to: \n" ); document.write( " \n" ); document.write( "Now we can add the fractions. (Leave the denominators factored for now.): \n" ); document.write( " \n" ); document.write( "which does not match any of the provided answers. I don't see any errors so I must assume that there is something wrong in the problem you posted. I'm going to guess that the denominator of one of the last two fractions should be n-2 and not n+2. So I am going to solve the problem again with a n-2 denominator. (It doesn't matter which fraction because they are both the same.) I am not going to provide commentary this time. The logic is the same as above except, since the last two fractions no longer have the same denominator to start with, I will not be adding the last two fractions so early. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "which doesn't match any of the provided answers either. I still see no errors in my work so I have to assume that either the provided answers are in correct or both the original equation and the one I guessed at are also wrong. But perhaps you have seen enough here to figure out the actual problem. \n" ); document.write( " |