document.write( "Question 271386: simplify:
\n" ); document.write( "4n/ n squared - 4 minus 2/n + 2 minus 2/n + 2\r
\n" ); document.write( "\n" ); document.write( "a. 2/n - 2
\n" ); document.write( "b. 4n - 2/n squared - n - 6
\n" ); document.write( "c. 2/n + 2
\n" ); document.write( "d. 1/n - 1
\n" ); document.write( "Thanks
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Algebra.Com's Answer #199192 by jsmallt9(3758)\"\" \"About 
You can put this solution on YOUR website!
\"%284n%29%2F%28n%5E2-+4%29+-+2%2F%28n+%2B+2%29+-+2%2F%28n+%2B+2%29\"
\n" ); document.write( "Since subtractions can a source of errors for many people, I am going to start by changing the subtractions into additions:
\n" ); document.write( "\"%284n%29%2F%28n%5E2-+4%29+%2B+%28-2%29%2F%28n+%2B+2%29+%2B+%28-2%29%2F%28n+%2B+2%29\"
\n" ); document.write( "and the last two terms have the same denominator so I will go ahead and add them:
\n" ); document.write( "\"%284n%29%2F%28n%5E2-+4%29+%2B+%28-4%29%2F%28n+%2B+2%29\"
\n" ); document.write( "To add the remaining fractions we need to get a common denominator first. And to find the Lowest Common Denominator (LCD) we need to factor each denominator:
\n" ); document.write( "\"%284n%29%2F%28%28n%2B2%29%28n+-+2%29%29+%2B+%28-4%29%2F%28n+%2B+2%29\"
\n" ); document.write( "From this we can see that
  • the LCD is (n+2)(n-2)
  • the first fraction already has the LCD as the denominator
  • the part of the LCD missing in the second denominator is n-2

\n" ); document.write( "So we will multiply the numerator and denominator of the second fraction by n-2:
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\n" ); document.write( "which simplifies to:
\n" ); document.write( "\"%284n%29%2F%28%28n%2B2%29%28n+-+2%29%29+%2B+%28-4n+%2B+8%29%2F%28n+%2B+2%29%28n-2%29%29\"
\n" ); document.write( "Now we can add the fractions. (Leave the denominators factored for now.):
\n" ); document.write( "\"8%2F%28%28n%2B2%29%28n+-+2%29%29\"
\n" ); document.write( "which does not match any of the provided answers. I don't see any errors so I must assume that there is something wrong in the problem you posted. I'm going to guess that the denominator of one of the last two fractions should be n-2 and not n+2. So I am going to solve the problem again with a n-2 denominator. (It doesn't matter which fraction because they are both the same.) I am not going to provide commentary this time. The logic is the same as above except, since the last two fractions no longer have the same denominator to start with, I will not be adding the last two fractions so early.
\n" ); document.write( "\"%284n%29%2F%28n%5E2-+4%29+-+2%2F%28n+%2B+2%29+-+2%2F%28n+-+2%29\"
\n" ); document.write( "\"%284n%29%2F%28n%5E2-+4%29+%2B+%28-2%29%2F%28n+%2B+2%29+%2B+%28-2%29%2F%28n+-+2%29\"
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\n" ); document.write( "\"0%2F%28%28n%2B2%29%28n-2%29%29\"
\n" ); document.write( "\"0\"
\n" ); document.write( "which doesn't match any of the provided answers either. I still see no errors in my work so I have to assume that either the provided answers are in correct or both the original equation and the one I guessed at are also wrong. But perhaps you have seen enough here to figure out the actual problem.
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