document.write( "Question 272215: The averages speed of an automobile for the first half of a 100 km. trip was
\n" ); document.write( "60 km/hr and from the second half was 90 km/hr. What was the average speed in
\n" ); document.write( "km/hr for the entire distance?\r
\n" ); document.write( "\n" ); document.write( "(A) 68 (B) 72 (C) 75 D) 78 (E) 80
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #199191 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
Distance(d) equals Rate(r) times Time(t) or d=r/t; r=d/t and t=d/r\r
\n" ); document.write( "\n" ); document.write( "Average Speed=(Total Distance)/(Total Time)
\n" ); document.write( "Total Distance = 100km
\n" ); document.write( "Total Time=Time for the 1st half + Time for the 2nd half
\n" ); document.write( "Time for the 1st half=50/60=5/6 hr
\n" ); document.write( "Time for the 2nd half=50/90=5/9 hr
\n" ); document.write( "So,
\n" ); document.write( "Average Speed=100/(5/6+5/9)
\n" ); document.write( "Average Speed=100/(15/18 +10/18)
\n" ); document.write( "Average Speed=100/(25/18) multiply numerator and denominator by 18/25
\n" ); document.write( "Average Speed=100(18/25)/1=4*18=72 km/hr\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor
\n" ); document.write( "
\n" );