document.write( "Question 272215: The averages speed of an automobile for the first half of a 100 km. trip was
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document.write( "60 km/hr and from the second half was 90 km/hr. What was the average speed in
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document.write( "km/hr for the entire distance?\r
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document.write( "(A) 68 (B) 72 (C) 75 D) 78 (E) 80
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Algebra.Com's Answer #199191 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! Distance(d) equals Rate(r) times Time(t) or d=r/t; r=d/t and t=d/r\r \n" ); document.write( "\n" ); document.write( "Average Speed=(Total Distance)/(Total Time) \n" ); document.write( "Total Distance = 100km \n" ); document.write( "Total Time=Time for the 1st half + Time for the 2nd half \n" ); document.write( "Time for the 1st half=50/60=5/6 hr \n" ); document.write( "Time for the 2nd half=50/90=5/9 hr \n" ); document.write( "So, \n" ); document.write( "Average Speed=100/(5/6+5/9) \n" ); document.write( "Average Speed=100/(15/18 +10/18) \n" ); document.write( "Average Speed=100/(25/18) multiply numerator and denominator by 18/25 \n" ); document.write( "Average Speed=100(18/25)/1=4*18=72 km/hr\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor \n" ); document.write( " |