document.write( "Question 272201: If you double Lisa's age and then subtract 6, you get Paul's age. 2 years ago, the sum of their ages was 29. How old is each person? \n" ); document.write( "

Algebra.Com's Answer #199184 by mananth(16946) $\"\"$ $\"About$

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If you double Lisa's age and then subtract 6, you get Paul's age. 2 years ago, the sum of their ages was 29. How old is each person? \r
\n" ); document.write( "\n" ); document.write( "Let's assume Lisa's age to be x\r
\n" ); document.write( "\n" ); document.write( "double her age = 2x\r
\n" ); document.write( "\n" ); document.write( "subtract 6
\n" ); document.write( "2x-6 =paul's age\r
\n" ); document.write( "\n" ); document.write( "two years ago\r
\n" ); document.write( "\n" ); document.write( "lisa was x-2 years old\r
\n" ); document.write( "\n" ); document.write( "And paul was (2x-6)- 2\r
\n" ); document.write( "\n" ); document.write( "the sum of their ages was 29 2 years ago\r
\n" ); document.write( "\n" ); document.write( "x-2 + (2x-6) -2 =29\r
\n" ); document.write( "\n" ); document.write( "x-2 +2x-6 -2 =29\r
\n" ); document.write( "\n" ); document.write( "3x= 29+2+6+2\r
\n" ); document.write( "\n" ); document.write( "3x= 39
\n" ); document.write( "x= 39/3
\n" ); document.write( "x=13 \r
\n" ); document.write( "\n" ); document.write( "lisa's age = 13
\n" ); document.write( "and Paul's age = 26\r
\n" ); document.write( "\n" ); document.write( "Ananth professional online tutor\r
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