document.write( "Question 272163: how do you solve n÷7+3=(n+2)÷7+-5 \n" ); document.write( "
Algebra.Com's Answer #199176 by unlockmath(1688)![]() ![]() You can put this solution on YOUR website! Hello, \n" ); document.write( "With this: n÷7+3=(n+2)÷7+-5 let's get rid of the denominator by multiplying by 7 to result in: (Note: I'm reading this as (n÷7)+3=[(n+2)÷7]+-5 \n" ); document.write( "n+21=n+2-35 There's no solution \n" ); document.write( "Now if it's written this way n÷(7+3)=(n+2)÷(7+-5) it will be: \n" ); document.write( "n/10=(n+2)/2 Multiply both sides by 10 to get: \n" ); document.write( "n=5n+10 Subtract 5n from both sides to get: \n" ); document.write( "-4n=10 Divide both sides by -4 to get: \n" ); document.write( "n=-10/4 \n" ); document.write( "There we go. \n" ); document.write( "RJ \n" ); document.write( "Check out a book I wrote at: \n" ); document.write( "www.math-unlock.com \n" ); document.write( " |