document.write( "Question 272163: how do you solve n÷7+3=(n+2)÷7+-5 \n" ); document.write( "
Algebra.Com's Answer #199176 by unlockmath(1688)\"\" \"About 
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Hello,
\n" ); document.write( "With this: n÷7+3=(n+2)÷7+-5 let's get rid of the denominator by multiplying by 7 to result in: (Note: I'm reading this as (n÷7)+3=[(n+2)÷7]+-5
\n" ); document.write( "n+21=n+2-35 There's no solution
\n" ); document.write( "Now if it's written this way n÷(7+3)=(n+2)÷(7+-5) it will be:
\n" ); document.write( "n/10=(n+2)/2 Multiply both sides by 10 to get:
\n" ); document.write( "n=5n+10 Subtract 5n from both sides to get:
\n" ); document.write( "-4n=10 Divide both sides by -4 to get:
\n" ); document.write( "n=-10/4
\n" ); document.write( "There we go.
\n" ); document.write( "RJ
\n" ); document.write( "Check out a book I wrote at:
\n" ); document.write( "www.math-unlock.com
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