document.write( "Question 272187: the difference between the length and width of a rectangle is 7 centimeters. what is the dimensions of rectangle if its perimeter is 50 centimers \n" ); document.write( "

Algebra.Com's Answer #199174 by oberobic(2304) $\"\"$ $\"About$

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L = length
\n" ); document.write( "W = width
\n" ); document.write( "P = perimeter = 50
\n" ); document.write( "P = 2(L+W) = perimeter formula = 2L + 2W
\n" ); document.write( "L - W = 7 :: given
\n" ); document.write( "so
\n" ); document.write( "L = W+7
\n" ); document.write( ".
\n" ); document.write( "substituting
\n" ); document.write( "2(W+7) + 2W = 50
\n" ); document.write( "2W + 14 + 2W = 50
\n" ); document.write( "4W = 36
\n" ); document.write( "W = 9
\n" ); document.write( ".
\n" ); document.write( "L=W+7 = 9+7 = 16
\n" ); document.write( ".
\n" ); document.write( "checking
\n" ); document.write( "2L + 2W = 2(16) + 2(9) = 32+18 = 50
\n" ); document.write( ".
\n" ); document.write( "Answer:
\n" ); document.write( "L = 16
\n" ); document.write( "W = 9 \n" ); document.write( "

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