document.write( "Question 272095: The length of a rectangle is 5 inches more than the width. The perimeter is 34 inches. Find the length and width. Thank you. \n" ); document.write( "

Algebra.Com's Answer #199170 by oberobic(2304) $\"\"$ $\"About$

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L = length
\n" ); document.write( "W = width
\n" ); document.write( "L = W + 5 :: given
\n" ); document.write( "P = 2L + 2W :: known definition of the perimeter
\n" ); document.write( "P = 34 :: given
\n" ); document.write( ".
\n" ); document.write( "2L + 2W = 34
\n" ); document.write( "2(W+5) + 2W = 34
\n" ); document.write( "2W + 10 + 2W = 34
\n" ); document.write( "4W + 10 = 34
\n" ); document.write( "4W = 24
\n" ); document.write( "W = 6
\n" ); document.write( ".
\n" ); document.write( "L = W+5 = 6+5 = 11
\n" ); document.write( ".
\n" ); document.write( "checking perimeter
\n" ); document.write( "2L + 2W = 2(6) + 2(11) = 12 + 22 = 34
\n" ); document.write( "OK.
\n" ); document.write( ".
\n" ); document.write( "Answer:
\n" ); document.write( "L = 11
\n" ); document.write( "W = 6
\n" ); document.write( ".
\n" ); document.write( "Done \n" ); document.write( "

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