document.write( "Question 33527: This problem appeared on my test last night and it is really bothering me, could someone help!! The width of a rectangle is 3ft plus 2x it's length, and the area is 104. Can you tell me the dimensions?
\n" ); document.write( " (x)(2x+3)=104
\n" ); document.write( " 2x^2+3-104=0
\n" ); document.write( "(2x+ )(x- )
\n" ); document.write( "I can not seem to factor 104 to get to the number three to go any further.
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Algebra.Com's Answer #19917 by longjonsilver(2297)\"\" \"About 
You can put this solution on YOUR website!
\"+2x%5E2%2B3x-104+=+0+\"
\n" ); document.write( "(2x-13)(x+8) = 0
\n" ); document.write( "2x-13=0 or x+8=0
\n" ); document.write( "2x = 13 or x=-8
\n" ); document.write( "x = 13/2 or x=-8\r
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\n" ); document.write( "\n" ); document.write( "So, the rectangle is 6.5x16\r
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\n" ); document.write( "\n" ); document.write( "jon.
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