document.write( "Question 33525: the sum of the first nine terms of an arithmetic progression is 75 and the twenty-fifth is also 75. find the common difference and the sum of the first hundred terms. \n" ); document.write( "
Algebra.Com's Answer #19912 by longjonsilver(2297)\"\" \"About 
You can put this solution on YOUR website!
25th term is a+24d, so a+24d = 75 --eqn1\r
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\n" ); document.write( "\n" ); document.write( "Sum of 9 = \"+%28n%2F2%29%282a+%2B+%28n-1%29d%29+\"
\n" ); document.write( "\"+%289%2F2%29%282a+%2B+%289-1%29d%29+=+75+\"
\n" ); document.write( "\"+9%282a+%2B+8d%29+=+150+\"
\n" ); document.write( "\"+18a+%2B+72d+=+150+\"\r
\n" ); document.write( "\n" ); document.write( "Scale eqn1 by 3 to give 3a+72d = 225. So we have \r
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\n" ); document.write( "\n" ); document.write( "3a+72d = 225
\n" ); document.write( "18a+72d = 150\r
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\n" ); document.write( "\n" ); document.write( "Subtract, to give -15a = 75
\n" ); document.write( "--> a = -5\r
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\n" ); document.write( "\n" ); document.write( "So, from a+24d = 75 we get
\n" ); document.write( "-5+24d = 75
\n" ); document.write( "24d = 80
\n" ); document.write( "d = 80/24
\n" ); document.write( "d = 10/3\r
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\n" ); document.write( "\n" ); document.write( "This is:
\n" ); document.write( "-5, -5/3, 5/3, 5, 25/3, 35/3, 15, 55/3, 65/3,... which does add up to 75.\r
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\n" ); document.write( "\n" ); document.write( "So, Sum of 100 terms is \"+%28n%2F2%29%282a+%2B+%28n-1%29d%29+\"
\n" ); document.write( "\"+%28100%2F2%29%282%28-5%29+%2B+%28100-1%29%2810%2F3%29%29+\"
\n" ); document.write( "\"+50%28-10+%2B+%2899%29%2810%2F3%29%29+\"
\n" ); document.write( "50(-10 + 330)
\n" ); document.write( "50(320)
\n" ); document.write( "50(320)
\n" ); document.write( "16000\r
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\n" ); document.write( "\n" ); document.write( "jon.
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