document.write( "Question 272079: find the dimensions of a rectangle with an area of 60ft^2 and a diagonal of 13ft \n" ); document.write( "

Algebra.Com's Answer #199116 by checkley77(12844) $\"\"$ $\"About$

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XY=60 OR X=60/Y
\n" ); document.write( "X^2+Y^2=13^2
\n" ); document.write( "(60/Y)^2+Y^2=169
\n" ); document.write( "3600/Y^2+Y^2=169
\n" ); document.write( "(3600+Y^4)/Y^2=169
\n" ); document.write( "3600+Y^4=169Y^2
\n" ); document.write( "Y^4-169Y^2+3600=0
\n" ); document.write( "(Y^2-144)(Y^2-25)=0
\n" ); document.write( "(Y+12)(Y-12)(Y+5)(Y-5)=0
\n" ); document.write( "Y-12=0
\n" ); document.write( "Y=12 ANS.
\n" ); document.write( "X=60/12=5 ANS.
\n" ); document.write( "Y-5=0
\n" ); document.write( "Y=5 ANS.
\n" ); document.write( "X=60/5=12 ANS.
\n" ); document.write( "PROOF
\n" ); document.write( "12*5=60
\n" ); document.write( "12^2+5^2=169
\n" ); document.write( "144+25=169
\n" ); document.write( "169=159 \n" ); document.write( "

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