document.write( "Question 272078: y= -1/2x^2 + 2x + 10\r
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document.write( "I have the vertex (2, 12) and the y intercept (0,10) but I keep getting stuck with....
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document.write( "x= -b +/- the square root of b^2 - 4ac over 2a.\r
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document.write( "I have it down to x= -2+/- the square root of 24 over -1 from there I am stuck \n" );
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Algebra.Com's Answer #199110 by dabanfield(803)![]() ![]() ![]() You can put this solution on YOUR website! y= -1/2x^2 + 2x + 10 \n" ); document.write( "I have the vertex (2, 12) and the y intercept (0,10) but I keep getting stuck with.... \n" ); document.write( "x= -b +/- the square root of b^2 - 4ac over 2a. \n" ); document.write( "I have it down to x= -2+/- the square root of 24 over -1 from there I am stuck\r \n" ); document.write( "\n" ); document.write( "If you are supposed to solve the above for x we need to get the equation in the form:\r \n" ); document.write( "\n" ); document.write( "ax^2 + bx + c = 0\r \n" ); document.write( "\n" ); document.write( "-1/2x^2 + 2x + 10 = 0\r \n" ); document.write( "\n" ); document.write( "In this case we have a = -1/2, b = 2 and c = 10. Using the quadratic formula then gives you:\r \n" ); document.write( "\n" ); document.write( "-2 +- [sqrt(2^2 - 4*-1/2*10)]/(2*-1/2) =\r \n" ); document.write( "\n" ); document.write( "-2 +- sqrt(4 + 20)/-1 =\r \n" ); document.write( "\n" ); document.write( "-2 +- sqrt(24)/-1\r \n" ); document.write( "\n" ); document.write( "The two solutions then are:\r \n" ); document.write( "\n" ); document.write( "-2 - sqrt(24) and \n" ); document.write( "-2 + sqrt(24)\r \n" ); document.write( "\n" ); document.write( "sqrt(24) = sqrt(4*6) = sqrt(4)*sqrt(6) = 2*sqrt(6) so \n" ); document.write( "we can rewrite the solutions as:\r \n" ); document.write( "\n" ); document.write( "-2 - 2*sqrt(6) \n" ); document.write( "-2 + 2*sqrt(6) \n" ); document.write( " |