document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=272116>Question 272116</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The area of a rectangle with perimeter 100 in. is given by the formula:  A=50w-w^2 where w is the width.  Find the value of w that produces the maximum area. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #199107 by </B><A HREF=/tutors/aboutme.mpl?userid=palanisamy><B>palanisamy(496)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=palanisamy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=199107\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Given, Area A = 50w-w&2<BR>\n" );
document.write( "Differentiating withrespect to w, we get<BR>\n" );
document.write( "dA/dw= 50-2w<BR>\n" );
document.write( "For maximum or minimum value of A,<BR>\n" );
document.write( "dA/dw=0<BR>\n" );
document.write( "50-2w=0<BR>\n" );
document.write( "50=2w<BR>\n" );
document.write( "50/2=w<BR>\n" );
document.write( "w=25 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );