document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=272094>Question 272094</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi<BR>\n" );
document.write( "I'm working with Isosceles triangles.  I have (-9,-8) (-4,10)and (-4,-8)<BR>\n" );
document.write( "I think this is an Isosceles because the lengths of 2 sides are the same.  Is this correct?\r<BR>\n" );
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document.write( "Also, is the length of the base 5?<BR>\n" );
document.write( "And lastly I need to figure out the area.  I've been using the midpoint formula and am getting (-4,1) is this correct?  I'm then using the 1st point and the midpoint to plug into the distance formula.  I'm getting 106 under a square root sign.....Do I then use 10.29 to plug in the Area formula?  I'm trying A= 1/2 (base)5 (height) 10.29=25.73...I don't think I'm supposed to end up with a decimal.  Please help me find where I'm going wrong.<BR>\n" );
document.write( "Thanks<BR>\n" );
document.write( "Rachel </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #199100 by </B><A HREF=/tutors/aboutme.mpl?userid=dabanfield><B>dabanfield(803)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dabanfield><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=199100\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I'm working with Isosceles triangles. I have (-9,-8) (-4,10)and (-4,-8)<BR>\n" );
document.write( "I think this is an Isosceles because the lengths of 2 sides are the same. Is this correct? <BR>\n" );
document.write( "Also, is the length of the base 5?<BR>\n" );
document.write( "And lastly I need to figure out the area. I've been using the midpoint formula and am getting (-4,1) is this correct? I'm then using the 1st point and the midpoint to plug into the distance formula. I'm getting 106 under a square root sign.....Do I then use 10.29 to plug in the Area formula? I'm trying A= 1/2 (base)5 (height) 10.29=25.73...I don't think I'm supposed to end up with a decimal. Please help me find where I'm going wrong.<BR>\n" );
document.write( "Thanks<BR>\n" );
document.write( "Rachel<BR>\n" );
document.write( "0 solutions\r<BR>\n" );
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document.write( "Let's say point A is (-9,-8), B is (-4,-8) and C is (-4,10)\r<BR>\n" );
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document.write( "Side AB is sqrt((-8--8)^2 + (-4--9)^2) = sqrt(0^2 + 5^2) = 5<BR>\n" );
document.write( "Side BC is sqrt((10--8)^2 + (-4--4)^2) = sqrt(18^2+0^2) = sqrt(18^2) = 18<BR>\n" );
document.write( "Side AC is sqrt((10--8)^2 + (-4--9)^2) = sqrt(18^2+5^2) = sqrt(349)\r<BR>\n" );
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document.write( "The triangle is not isosceles :)\r<BR>\n" );
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document.write( "The area of the triangle is 1/2*base*height.<BR>\n" );
document.write( "The base of this triangle is side AB and the height is BC. (notice that B and C both have an x-coordinate of -4 so BC is vertical. The points A and B have the same y-coordinate of -8 so AB is horizontal. AB and BC form a right angle). \r<BR>\n" );
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document.write( "The area then is 1/2*5*18 = 45 </SPAN>\n" );
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