document.write( "Question 271986: Can someone please help me with this word problem:\r
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document.write( "The area of a rectangle with the perimeter 100 in. is given by the formula: A=50w-w^2 where w is the width. Find the value of w that produces the maximum area. \r
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document.write( "the only way i could try to figure this out is to make columns with the length and width dimensions that equal 100 in perimeter and plug the width into the equation. I started using the width of 45 and worked down to 30 which has the area of 600. But since a square is also a rectangle, do I use 25? Is there an easier way to figure this? Thanks \n" );
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Algebra.Com's Answer #199053 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! The area of a rectangle with the perimeter 100 in. \n" ); document.write( " is given by the formula: A=50w-w^2 where w is the width. \n" ); document.write( " Find the value of w that produces the maximum area. \n" ); document.write( ": \n" ); document.write( "There is an easy way, this is a quadratic equation, \n" ); document.write( "then put the given equation A = 50w - w^2 in the form y = ax^2 + bx + c \n" ); document.write( "y = -w^2 + 50w where: a=-1, b=50 \n" ); document.write( ": \n" ); document.write( "Find the axis of symmetry using the formula x = -b/(2a), in this equation \n" ); document.write( "w = \n" ); document.write( "w = \n" ); document.write( "w = 25 in will produce max area \n" ); document.write( ": \n" ); document.write( "The max area of any rectangle is a square, a fact to remember. \n" ); document.write( " |