document.write( "Question 271990: 6^x-3=2^x \n" ); document.write( "
Algebra.Com's Answer #199050 by Alan3354(69443)\"\" \"About 
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If it's
\n" ); document.write( "6^(x-3) = 2^x, then
\n" ); document.write( "(x-3)*log(6) = x*log(2)
\n" ); document.write( "x*log(6) - 3log(6) = x*log(2)
\n" ); document.write( "x(log(6) - log(2)) = 3log(6)
\n" ); document.write( "x*log(3) = 3log(6)
\n" ); document.write( "x = 3log(6)/log(3)
\n" ); document.write( "x =~4.89279
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