document.write( "Question 271954: If k(2x + 3)(x – 1) = 0 and x > 1, what is the value of k? \r
\n" );
document.write( "\n" );
document.write( "A -3/2 b 0 c 2/3 d 1 e 2\r
\n" );
document.write( "\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #199043 by palanisamy(496)![]() ![]() ![]() You can put this solution on YOUR website! Given, k(2x + 3)(x – 1) = 0 \n" ); document.write( "So either k=0 or 2x+3=0 or x-1=0 \n" ); document.write( "k=0 or x=-3/2 or x=1 \n" ); document.write( "Since x>1, we must have k=0 \n" ); document.write( " |