document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=271954>Question 271954</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If  k(2x + 3)(x – 1) = 0 and x > 1,   what is the value of k? \r<BR>\n" );
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document.write( "A  -3/2   b 0    c  2/3    d 1     e 2\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #199040 by </B><A HREF=/tutors/aboutme.mpl?userid=dabanfield><B>dabanfield(803)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dabanfield><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=199040\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If k(2x + 3)(x – 1) = 0 and x > 1, what is the value of k? <BR>\n" );
document.write( "A -3/2 b 0 c 2/3 d 1 e 2 \r<BR>\n" );
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document.write( "For the product to be 0 at least one of the factors must be 0. Since x > 1, both 2x+3 and x-1 are greater than 0. So we must have k = 0. </SPAN>\n" );
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