document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=271973>Question 271973</A>: <I><SPAN STYLE=\"word-break: break-all;\"> John is 13 years less than 3 times as old as his son. Six years ago, he was 14 years more than twice as old as his son was then. How old is John?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #199021 by </B><A HREF=/tutors/aboutme.mpl?userid=dabanfield><B>dabanfield(803)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dabanfield><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=199021\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> John is 13 years less than 3 times as old as his son. Six years ago, he was 14 years more than twice as old as his son was then. How old is John? \r<BR>\n" );
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document.write( "Let x be the age of John's son and y be John's age. Six years ago John was y-6 year old and his son was x-6. Then we have:\r<BR>\n" );
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document.write( "1.) y = 3*x - 13  and<BR>\n" );
document.write( "2.) y-6 = 2*(x-6) + 14\r<BR>\n" );
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document.write( "Substitute 3x-13 for y (from 1.) in equation 2.):\r<BR>\n" );
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document.write( "3x-13 - 6 = 2*(x-6) + 14<BR>\n" );
document.write( "3x-19 = 2x-12+14\r<BR>\n" );
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document.write( "Solve the above for x and then calculate y = 3x-13. </SPAN>\n" );
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