document.write( "Question 271961: Ms. Jackson let her students know that their final exam contained three groups of questions:
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document.write( "- 16 multiple choice worth 1.5 points each
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document.write( "- 16 short answer worth 2.5 points each
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document.write( "- 3 essay one worth 12 points each\r
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document.write( "A. What percent of the final exam is each group worth?\r
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document.write( "B. Beatrice has a semester average of 89 before she takes the final. She knows that the final is worth 25% of her total semester average. What is the greatest number of questions Beatrice can miss and still raise her final semester average to at least a 90? Explain how you arrived at your answer \n" );
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Algebra.Com's Answer #199002 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! A) \n" ); document.write( "16*1.5+16*2.5+3*12=100 points for the exam. \n" ); document.write( "multiple choice is 16*1.5 =24 percent of the exam \n" ); document.write( "short answer is 16*2.5 =40 percent of the exam \n" ); document.write( "essay=3*12=36 percent of the exam\r \n" ); document.write( "\n" ); document.write( "B) \n" ); document.write( ".25*x+.75*89=90 \n" ); document.write( "x=93 \n" ); document.write( "She needs to get a 93 on the exam. \n" ); document.write( "So she can't lose more than 7 points to get her 90 average.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |