document.write( "Question 271877: Cherry is 30 years old, while her daughter kaye is 3 years old. When will she be 4 times as old as her daughter?\r
\n" ); document.write( "\n" ); document.write( "could you please answer my question? thank you. \n" ); document.write( "
Algebra.Com's Answer #199000 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Cherry is 30 years old, while her daughter kaye is 3 years old.
\n" ); document.write( " When will she be 4 times as old as her daughter?
\n" ); document.write( ":
\n" ); document.write( "Let y = no. of years for this to be true
\n" ); document.write( ":
\n" ); document.write( "Cherry + y = 4 times Kaye + y
\n" ); document.write( "30 + y = 4(3 + y)
\n" ); document.write( ":
\n" ); document.write( "30 + y = 12 + 4y
\n" ); document.write( ":
\n" ); document.write( "30 - 12 = 4y - y
\n" ); document.write( ":
\n" ); document.write( "18 = 3y
\n" ); document.write( "y = \"18%2F3\"
\n" ); document.write( "y = 6 years
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "See if this is true
\n" ); document.write( "Cherry will be 36, and Kaye will be 9; (4*9 = 36) \n" ); document.write( "
\n" );