document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=588>Question 588</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I use substitution usin this problem 2x-y=5; 3x-2y=9? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #199 by </B><A HREF=/tutors/aboutme.mpl?userid=citychic3><B>citychic3(8)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=citychic3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=199\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> change <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2x-y=5 ALIGN=MIDDLE  ALT=\"2x-y=5\"   DISABLED_style= \"max-width:90%; height:auto;\" > to <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=-5%2B2x ALIGN=MIDDLE  ALT=\"y=-5%2B2x\"   DISABLED_style= \"max-width:90%; height:auto;\" > then substitute into second equation thus: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3x-2%28-5%2B2x%29=9 ALIGN=MIDDLE  ALT=\"3x-2%28-5%2B2x%29=9\"   DISABLED_style= \"max-width:90%; height:auto;\" > solve: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=1 ALIGN=MIDDLE  ALT=\"x=1\"   DISABLED_style= \"max-width:90%; height:auto;\" > then substitute x=1 into the first equation thus: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%281%29-y=5 ALIGN=MIDDLE  ALT=\"2%281%29-y=5\"   DISABLED_style= \"max-width:90%; height:auto;\" > and solve: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=Y=-3 ALIGN=MIDDLE  ALT=\"Y=-3\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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