document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=271934>Question 271934</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Diagonal of a rectangle is 15 m. Longer side of rectangle is 12 m. What is perimeter of the rectangle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #198988 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=198988\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Diagonal of a rectangle is 15 m. Longer side of rectangle is 12 m. What is perimeter of the rectangle?\r<BR>\n" );
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document.write( "The diagonal and the two adjacent sides form a right triangle\r<BR>\n" );
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document.write( "Applying the pytahagoras theorem\r<BR>\n" );
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document.write( "Diagonal^2 = Length^2 + width^2\r<BR>\n" );
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document.write( "15^2= 12^2 +w^2\r<BR>\n" );
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document.write( "15^2-12^2 = width^2\r<BR>\n" );
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document.write( "225-144 = width^2\r<BR>\n" );
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document.write( "81=width^2\r<BR>\n" );
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document.write( "9= width\r<BR>\n" );
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document.write( "9*2 + 12*2 = perimeter<BR>\n" );
document.write( "18+24 = 42 meters\r<BR>\n" );
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