document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=271906>Question 271906</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The greenhouse floor has a diagonal equal to 28 feet.  the sides are sguare.  what is the length of one side?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #198983 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16949)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=198983\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The greenhouse floor has a diagonal equal to 28 feet.  the sides are sguare.  what is the length of one side?\r<BR>\n" );
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document.write( "Since it is a square floor the sides are equal.\r<BR>\n" );
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document.write( "Let each side be x\r<BR>\n" );
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document.write( "The diagonal and the two sides form a right triangle. The diagonal beomes the hyotenuse.\r<BR>\n" );
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document.write( "Using the Pythagorus theorem : (side)^2 +(side)^2 = Hypotenuse ^2\r<BR>\n" );
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document.write( "x^2+x^2 = 28^2<BR>\n" );
document.write( "2x^2=784\r<BR>\n" );
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document.write( "x^2= 784/2\r<BR>\n" );
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document.write( "x^2= 392<BR>\n" );
document.write( "x= sqrt 392 \r<BR>\n" );
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document.write( "x=19.79<BR>\n" );
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