document.write( "Question 33514: I have 23 coins...dimes, nickels, quarters...that equal $2.45. I must have twice the number of nickels as dimes. I know the answer is 12 nickels, 6 dimes and 5 quarters, but I don't know how to write the equation. Thanks in advance for your help.\r
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document.write( "I didn't submit an ISBN number...this problem was on a handwritten worksheet from the teacher. \n" );
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Algebra.Com's Answer #19897 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Let #of dimes be \"x\". \n" ); document.write( "Then # of nickels is \"2x\" \n" ); document.write( "And # of quarters is \"23-x-2x\"= \"23-3x\" \n" ); document.write( "Value of dimes is 10x cents \n" ); document.write( "Value of nickels is 5(2x)=10x cents \n" ); document.write( "Value of quarters is 25(23-3x)= 525-75x cents \n" ); document.write( "EQUATION: \n" ); document.write( " value + value + value = 245 cents \n" ); document.write( " 10x + 10x + 525-75x = 245 \n" ); document.write( "-55x=-330 \n" ); document.write( "x=6 (number of dimes \n" ); document.write( "2x = 12 (number of nickels) \n" ); document.write( "23-3x=23-18= 5 (number of quarters)\r \n" ); document.write( "\n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |