document.write( "Question 271879: 1.solve for x
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document.write( "log4 x^5=-1\r
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document.write( "2.solve for x in terms of k
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document.write( "log9 x + log9(x+9)=k\r
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document.write( "x=?
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document.write( "find x if k = 10\r
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Algebra.Com's Answer #198958 by dabanfield(803)![]() ![]() ![]() You can put this solution on YOUR website! 1.solve for x \n" ); document.write( "log4 x^5=-1 \n" ); document.write( "2.solve for x in terms of k \n" ); document.write( "log9 x + log9(x+9)=k \n" ); document.write( "x=? \n" ); document.write( "find x if k = 10 \r \n" ); document.write( "\n" ); document.write( "1.) log (base 4) x^5 = -1 so \n" ); document.write( " 5*log (base 4) x = -1 \n" ); document.write( " log (base 4) x = -1/5 so by definition of the log then \n" ); document.write( " 4^(-1/5) = x\r \n" ); document.write( "\n" ); document.write( "2.) log9 x + log9 (x+9) = k so \n" ); document.write( " log9 (9*(x+9)) = k so by definition of a log: \n" ); document.write( " 9^k = 9*(x+9) \n" ); document.write( " 9^k = 9x + 81 \n" ); document.write( " 9x = 9^k-81 \n" ); document.write( " x = 9^k/9-(81/9) \n" ); document.write( " x = 9^(k-1) - 9\r \n" ); document.write( "\n" ); document.write( "When k = 10 then x = 9^(10-1)- 9 \n" ); document.write( " x = 9^9 - 9 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |