document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=271807>Question 271807</A>: <I><SPAN STYLE=\"word-break: break-all;\"> when the lesser of two consecutive integers is added to three times the greater, the result is 43.  Find the integers? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #198954 by </B><A HREF=/tutors/aboutme.mpl?userid=dabanfield><B>dabanfield(803)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dabanfield><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=198954\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> when the lesser of two consecutive integers is added to three times the greater, the result is 43. Find the integers?\r<BR>\n" );
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document.write( "Let x be the smaller of the integers.  Then the other is x+1 and we have:\r<BR>\n" );
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document.write( "x + 3*(x+1) = 43\r<BR>\n" );
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document.write( "x + 3x + 3 = 43<BR>\n" );
document.write( "4x = 40<BR>\n" );
document.write( "x = 10<BR>\n" );
document.write( "x+1 = 11 </SPAN>\n" );
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