document.write( "Question 271696: Solve the following 3 by 3 system algebraically.
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document.write( "x+y+2z=0
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document.write( "1/4x-1/4y+1/8z=1
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document.write( "3/2x+y+1/2z=1 \n" );
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Algebra.Com's Answer #198931 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! I'm not sure what \"algebraically\" means. \n" ); document.write( "------------- \n" ); document.write( "x+y+2z=0 \n" ); document.write( "1/4x-1/4y+1/8z=1 --> 2x-2y+z = 8 \n" ); document.write( "3/2x+y+1/2z=1 --> 3x+2y+z = 2 \n" ); document.write( "--------------- \n" ); document.write( "x + y+2z = 0 \n" ); document.write( "2x-2y +z = 8 \n" ); document.write( "3x+2y +z = 2 \n" ); document.write( "Eliminate y \n" ); document.write( "------------ \n" ); document.write( "Add eqns 2 and 3 \n" ); document.write( "2x-2y +z = 8 \n" ); document.write( "3x+2y +z = 2 \n" ); document.write( "------------- Add \n" ); document.write( "5x + 2z = 10 eqn A \n" ); document.write( "-------------- \n" ); document.write( "Add 2x 1st eqn to 2nd \n" ); document.write( "2x+2y+4z = 0 \n" ); document.write( "2x-2y +z = 8 \n" ); document.write( "------------Add \n" ); document.write( "4x + 5z = 8 eqn B \n" ); document.write( "20x +25z = 40 eqn B x 5 \n" ); document.write( "20x + 8z = 40 eqn A x 4 \n" ); document.write( "------------------------ Subtract \n" ); document.write( "17z = 0 \n" ); document.write( "z = 0 \n" ); document.write( "------ \n" ); document.write( "x = 2 \n" ); document.write( "----- \n" ); document.write( "y = -2 \n" ); document.write( " \n" ); document.write( " |