document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=271640>Question 271640</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A two-digit number is five times the sum of its digits. The digits from left to right name consecutive integers. Find the number. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #198883 by </B><A HREF=/tutors/aboutme.mpl?userid=dabanfield><B>dabanfield(803)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dabanfield><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=198883\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A two-digit number is five times the sum of its digits. The digits from left to right name consecutive integers. Find the number.<BR>\n" );
document.write( "0 solutions\r<BR>\n" );
document.write( "\n" );
document.write( "Let x be the tens digit. Then the ones digit is the next consecutive integer or x+1.\r<BR>\n" );
document.write( "\n" );
document.write( "The number then is 10*x + 1*(x+1).\r<BR>\n" );
document.write( "\n" );
document.write( "So we have:\r<BR>\n" );
document.write( "\n" );
document.write( "10*x + 1*(x+1) = 5*((x + (x + 1))<BR>\n" );
document.write( "10x + x + 1 = 5*(2x + 1)<BR>\n" );
document.write( "11x + 1 = 10x + 5\r<BR>\n" );
document.write( "\n" );
document.write( "Solve the above for x and then calculate x+1.  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );