document.write( "Question 271711: Pls help me with this question. James walks a distance of 10km at an average speed of xkm/h.Jane walks the same distance at (x-1)km/h.If the difference in their times is 30minutes, find the value of x. \n" ); document.write( "

Algebra.Com's Answer #198865 by dabanfield(803) $\"\"$ $\"About$

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Pls help me with this question. James walks a distance of 10km at an average speed of xkm/h.Jane walks the same distance at (x-1)km/h.If the difference in their times is 30minutes, find the value of x.\r
\n" ); document.write( "\n" ); document.write( "Let t be the time needed for James to walk the distance:\r
\n" ); document.write( "\n" ); document.write( "Then since distance = rate x time we have:\r
\n" ); document.write( "\n" ); document.write( "1.) 10 = x*t or
\n" ); document.write( " t = 10/x \r
\n" ); document.write( "\n" ); document.write( "Jane walks the same distance in t+30 so we have:\r
\n" ); document.write( "\n" ); document.write( "2.) 10 = (x-1)*(t+30)\r
\n" ); document.write( "\n" ); document.write( "Substitute 10/x for t in equation 2.) giving:\r
\n" ); document.write( "\n" ); document.write( "10 = (x-1)*((10/x)+30)
\n" ); document.write( "10 = (10/x)*x - 10/x +30x - 30
\n" ); document.write( "10 = 10 - 10/x + 30x - 30
\n" ); document.write( "30x - 10/x = 30\r
\n" ); document.write( "\n" ); document.write( "Multiply both sides above by x:\r
\n" ); document.write( "\n" ); document.write( "30x^2 - 10 = 30x
\n" ); document.write( "30x^2 - 30x - 10 = 0\r
\n" ); document.write( "\n" ); document.write( "Solve the above quadratic equation for x using the quadratic formula. \n" ); document.write( "

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