document.write( "Question 271644: Cyclist A started his journey on cycle at 7:30 a.m. at a speed of 8 km/h. After 30 minutes, cyclist B started from the same place but with a speed of 10 km/h. At what time did B overtake A? \n" ); document.write( "
Algebra.Com's Answer #198822 by mananth(16946)\"\" \"About 
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Cyclist A started his journey on cycle at 7:30 a.m. at a speed of 8 km/h. After 30 minutes, cyclist B started from the same place but with a speed of 10 km/h. At what time did B overtake A?\r
\n" ); document.write( "\n" ); document.write( "A- 8 km/hr\r
\n" ); document.write( "\n" ); document.write( "B 10 km/hr\r
\n" ); document.write( "\n" ); document.write( "distance traveled by A in 1/2 hour = 4 kms.\r
\n" ); document.write( "\n" ); document.write( "x/10 = x-4 / 8\r
\n" ); document.write( "\n" ); document.write( "10*(x-4)= 8x\r
\n" ); document.write( "\n" ); document.write( "10x-40=8x
\n" ); document.write( "10x-8x= 40
\n" ); document.write( "2x=40
\n" ); document.write( "x=20\r
\n" ); document.write( "\n" ); document.write( "They meet after a distance of 20 km.\r
\n" ); document.write( "\n" ); document.write( "time taken = distance / speed \r
\n" ); document.write( "\n" ); document.write( "20 /10 = 2 hours\r
\n" ); document.write( "\n" ); document.write( "B overtakes A at 9.30 am.\r
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