document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=271578>Question 271578</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help :)\r<BR>\n" );
document.write( "\n" );
document.write( "1.Evaluate:<BR>\n" );
document.write( "a) (8/27)^(-4/3)<BR>\n" );
document.write( "b)[(3/5)^-1 - 4^0] ^-2 -- I got 9/4.\r<BR>\n" );
document.write( "\n" );
document.write( "2.Which is equivalent to:\r<BR>\n" );
document.write( "\n" );
document.write( "a)[(25^x)]/[125^(x+1)(5)] Is it 5^x+2 ?<BR>\n" );
document.write( "b) [(9^x)]/[(27^2x)(3)]  Is it 3^4x-1 ?<BR>\n" );
document.write( "c) (1/36)^x-2   Is it 6^-2x+4 ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #198787 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=198787\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> b)[(3/5)^-1 - 4^0] ^-2<BR>\n" );
document.write( "=[5/3 - 1]^-2<BR>\n" );
document.write( "=[2/3]^-2<BR>\n" );
document.write( "=[3/2]^2<BR>\n" );
document.write( "=9/4 Very good.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );