document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=33508>Question 33508</A>: <I><SPAN STYLE=\"word-break: break-all;\"> May you please help me simplify: (a^4+b^4)/(a^2+b^2) and (3+2i)/(3-2i)? I spent a while looking through previously answered questions but couldn't find a similar enough problem. Thank you for your help. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #19878 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=19878\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1st: If you do the problem using long division you get <BR>\n" );
document.write( "Quotient = a^2-b^2 and a Remainder of 2b^2/(a^2+b^2).\r<BR>\n" );
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document.write( "2nd: (3+2i)/(3-2i)<BR>\n" );
document.write( "Multiply numerator and denominator by (3+2i) to get:<BR>\n" );
document.write( "(3+2i)^2/(9+4)<BR>\n" );
document.write( "=[9-4+12i]/13<BR>\n" );
document.write( "=[5+12i]/13<BR>\n" );
document.write( "=(5/13)+(12/13)i<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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