document.write( "Question 271451: During the day a truck driver encounters light ,moderate, & heavy traffic. If he travels 1/3 hour in light, 1/2 hour in moderate, and 1/5 hour in heavy he can cover 21 miles. Ifh e travels 1/5 in light, 1/4 in moderate, and 1 hr in heavy he can cover 16 mi. The sum of his speeds in moderate & heavy is 5 mi less than his speed in light. Find his speed in each type of traffic.\r
\n" ); document.write( "\n" ); document.write( "Use 3 variable system to solve.
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Algebra.Com's Answer #198745 by ankor@dixie-net.com(22740)\"\" \"About 
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During the day a truck driver encounters light ,moderate, & heavy traffic.
\n" ); document.write( " If he travels 1/3 hour in light, 1/2 hour in moderate, and 1/5 hour in heavy he can cover 21 miles.
\n" ); document.write( " If he travels 1/5 in light, 1/4 in moderate, and 1 hr in heavy he can cover 16 mi.
\n" ); document.write( " The sum of his speeds in moderate & heavy is 5 mi less than his speed in light.
\n" ); document.write( "Find his speed in each type of traffic. :
\n" ); document.write( ":
\n" ); document.write( "Three different speed, fast, medium, slow: a, b, c
\n" ); document.write( ":
\n" ); document.write( "A first distance equation
\n" ); document.write( "\"1%2F3\"a + \"1%2F2\"b + \"1%2F5\"c = 21
\n" ); document.write( "Multiply by 30 to get rid of the fractions, results:
\n" ); document.write( "10a + 15b + 6c = 30(21)
\n" ); document.write( "10a + 15b + 6c = 630
\n" ); document.write( ":
\n" ); document.write( "2nd distance equation
\n" ); document.write( "\"1%2F5\"a + \"1%2F4\"b + c = 16
\n" ); document.write( "Multiply by 20 to get rid of the fractions, results:
\n" ); document.write( "4a + 5b + 20c = 20(16)
\n" ); document.write( "4a + 5b + 20c = 320
\n" ); document.write( ":
\n" ); document.write( "\"The sum of his speeds in moderate & heavy is 5 mi less than his speed in light.\"
\n" ); document.write( "b + c = a - 5
\n" ); document.write( "-a + b + c = -5
\n" ); document.write( ":
\n" ); document.write( "Using the matrix feature in a Ti83,
\n" ); document.write( "10, 15, 6, 630
\n" ); document.write( "4, 5, 20, 320
\n" ); document.write( "-1,1, 1, -5
\n" ); document.write( "I got
\n" ); document.write( "a = 30 mph
\n" ); document.write( "b = 20
\n" ); document.write( "c = 5
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