document.write( "Question 271392: Two jets are traveling toward each other and are 4000km apart. THe rate of one jet is 100km/h faster than the rate of the other. if the jets pass each other after 2.5 hrs., what is the rate of the faster jet? pleaaseee i need help coming up with the equations! \n" ); document.write( "
Algebra.Com's Answer #198732 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! D=RT \n" ); document.write( "4,000=(X+X+100)2.5 \n" ); document.write( "4,000=(2X+100)2.5 \n" ); document.write( "4,000=5X+250 \n" ); document.write( "5X=4,000-250 \n" ); document.write( "5X=3,750 \n" ); document.write( "X=3,750/5 \n" ); document.write( "X=750 KMH. SPEED OF THE SLOWER PLANE. \n" ); document.write( "750+100=850 KMH SPEED OF THE FASTER PALNE. \n" ); document.write( "PROOF: \n" ); document.write( "4,000=(750+850)2.5 \n" ); document.write( "4,000=1,600*2.5 \n" ); document.write( "4,000=4,000 \n" ); document.write( " \n" ); document.write( " |