document.write( "Question 271392: Two jets are traveling toward each other and are 4000km apart. THe rate of one jet is 100km/h faster than the rate of the other. if the jets pass each other after 2.5 hrs., what is the rate of the faster jet? pleaaseee i need help coming up with the equations! \n" ); document.write( "
Algebra.Com's Answer #198732 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
D=RT
\n" ); document.write( "4,000=(X+X+100)2.5
\n" ); document.write( "4,000=(2X+100)2.5
\n" ); document.write( "4,000=5X+250
\n" ); document.write( "5X=4,000-250
\n" ); document.write( "5X=3,750
\n" ); document.write( "X=3,750/5
\n" ); document.write( "X=750 KMH. SPEED OF THE SLOWER PLANE.
\n" ); document.write( "750+100=850 KMH SPEED OF THE FASTER PALNE.
\n" ); document.write( "PROOF:
\n" ); document.write( "4,000=(750+850)2.5
\n" ); document.write( "4,000=1,600*2.5
\n" ); document.write( "4,000=4,000
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