document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=271363>Question 271363</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve for X and Y in the following problems using either substitution or elimination methods.  X + Y = 10,  3X + Y = 12 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #198715 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=198715\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3X+Y=12<BR>\n" );
document.write( "-(X+Y=10)<BR>\n" );
document.write( "----------------<BR>\n" );
document.write( "2X=2<BR>\n" );
document.write( "X=2/2<BR>\n" );
document.write( "X=1 ANS.<BR>\n" );
document.write( "3*1+Y=12<BR>\n" );
document.write( "3+Y=12<BR>\n" );
document.write( "Y=12-3<BR>\n" );
document.write( "Y=9 ANS.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "1+9=10<BR>\n" );
document.write( "10=10<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );