document.write( "Question 33504: sqrt(2x-5) - sqrt(x-3) = 1 \n" ); document.write( "
Algebra.Com's Answer #19871 by mukhopadhyay(490)\"\" \"About 
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sqrt(2x-5) - sqrt(x-3) = 1
\n" ); document.write( "=> sqrt(2x-5) = 1 + sqrt(x-3)
\n" ); document.write( "=> ]sqrt(2x-5)]^2 = [1 + sqrt(x-3)]^2
\n" ); document.write( "=> 2x-5 = 1+x-3+2sqrt(x-3)
\n" ); document.write( "=> x-3 = 2sqrt(x-3)
\n" ); document.write( "=> [x-3]^2 = [2sqrt(x-3)]^2
\n" ); document.write( "=> [x-3]^2 = 4(x-3)
\n" ); document.write( "=> (x-3)(x-3-4) = 0
\n" ); document.write( "=> (x-3)(x-7) = 0
\n" ); document.write( "=> x=3 or x=7\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
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