document.write( "Question 4350: solve the quadratic equation x squared+4x-5=0 by completing squares.\r
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Algebra.Com's Answer #1987 by rapaljer(4671)![]() ![]() You can put this solution on YOUR website! Begin by adding 5 to each side to set up the \"completing the square\" process.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Take half of the 4 and square, which is 2 squared, or 4. Add 4 to each side of the equation to create a perfect square trinomial on the left side.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Take the square root of both sides:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Subtract 2 from each side:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In the first case, x = -2 + 3 = 1 \n" ); document.write( "In the second case, x = -2 - 3 = -5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Check answers: \n" ); document.write( "\n" ); document.write( "For x = 1, \n" ); document.write( "For x = -5, \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Both answers check!\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "R^2 at SCC\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |