document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=271334>Question 271334</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Four time the smallest of three consecutive odd integers is 236 more than the sum of the other two intergers.  Find the integers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #198679 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=198679\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x, x+2 & x+4 be the 3 odd integers.<BR>\n" );
document.write( "4x=236+(x+2)+(x+4)<BR>\n" );
document.write( "4x=236+2x+6<BR>\n" );
document.write( "4x-2x=242<BR>\n" );
document.write( "2x=242<BR>\n" );
document.write( "x=242/2<BR>\n" );
document.write( "x=121 ans. for the smallest integer.<BR>\n" );
document.write( "121+2=123 for the middle integer.<BR>\n" );
document.write( "121+4=125 for the largest integer.<BR>\n" );
document.write( "Proof;<BR>\n" );
document.write( "4*121=236+123+125<BR>\n" );
document.write( "484=484 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );