document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=271287>Question 271287</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many liters of a 40% antifreeze solution must be mixed with 5 liters of a 70% antifreeze solution to make a mixture that is 60% antifreeze?\r<BR>\n" );
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document.write( "I can't figure out how to set this up. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #198629 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=198629\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How many liters of a 40% antifreeze solution must be mixed with 5 liters of a 70% antifreeze solution to make a mixture that is 60% antifreeze? <BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "alcohol + alcohol = alcohol<BR>\n" );
document.write( "0.40x + 0.70*5 = 0.60(x+5)<BR>\n" );
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document.write( "Multiply thru by 100<BR>\n" );
document.write( "40x + 70*5 = 60x + 60*5<BR>\n" );
document.write( "-20x = -10*5<BR>\n" );
document.write( "x = 2.5 liters (amt. of 40% solution needed in the mixture)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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