document.write( "Question 271214: One number is four more than a second number. Two times the first number is 10 more that four times the second number. \n" ); document.write( "
Algebra.Com's Answer #198607 by Stitch(470)\"\" \"About 
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Equation 1: \"A+=+4+%2B+B\"
\n" ); document.write( "Equation 2: \"2A+=+10+%2B+4B\"\r
\n" ); document.write( "\n" ); document.write( "Solution:
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\n" ); document.write( "We can take the (4 + B) from equation 1 and substitute it into equation 2 for A
\n" ); document.write( "Equation 2: \"2A+=+10+%2B+4B\"
\n" ); document.write( "\"2%2A%284+%2B+B%29+=+10+%2B+4B\" Simplify
\n" ); document.write( "\"8+%2B+2B+=+10+%2B+4B\" Subtract 10 from both sides
\n" ); document.write( "\"8+%2B+2B+-+10+=+4B\" Subtract 2B from both sides
\n" ); document.write( "\"8+-+10+=+4B+-+2b\" Simplify
\n" ); document.write( "\"-2+=+2B\" Divide both sides by 2
\n" ); document.write( "\"highlight%28-1+=+B%29\"\r
\n" ); document.write( "\n" ); document.write( "Now we can plug -1 into equation 1 for B
\n" ); document.write( "Equation 1: \"A+=+4+%2B+B\"
\n" ); document.write( "\"A+=+4+%2B+%28-1%29\" Simplify
\n" ); document.write( "\"highlight%28A+=+3%29\"\r
\n" ); document.write( "\n" ); document.write( "Check the answer:
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\n" ); document.write( "Plug your values back into equation 2
\n" ); document.write( "Equation 2: \"2A+=+10+%2B+4B\"
\n" ); document.write( "\"2%2A%283%29+=+10+%2B+4%2A%28-1%29\" Simplify
\n" ); document.write( "\"highlight%286+=+6%29\"
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