document.write( "Question 271209: how much pure acid should be mixed with 2 gallons of a 40% acid solution in order to get a 70% acid solution \n" ); document.write( "

Algebra.Com's Answer #198606 by Earlsdon(6294) $\"\"$ $\"About$

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Let x = the number of galons of pure acid to be added to the 2 gallons of 40% acid solution to obtain (2+x) gallons of 70% acid solution. You can express this algebraically as: (40% = 0.4) and (70% = 0.7)
\n" ); document.write( "x + 2(0.4) = (2+x)(0.7) Simplify and solve for x.
\n" ); document.write( "x+0.8 = 1.4+0.7x Subtract 0.7x from both sides.
\n" ); document.write( "0.3x+0.8 = 1.4 Now subtract 0.8 from both sides.
\n" ); document.write( "0.3x = 0.6 Finally, divide both sides by 0.3
\n" ); document.write( "x = 2
\n" ); document.write( "You will need to mix 2 gallons of pure acid to the 2 gallons of 40% acid solution to obtain 4 gallons of 70% acid solution. \n" ); document.write( "

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