document.write( "Question 271197: One number is 5 more than twice the other. The sum of their squares is 325. Find the numbers.
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Algebra.Com's Answer #198599 by checkley77(12844)\"\" \"About 
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x=2y+5
\n" ); document.write( "x^2+y^2=325
\n" ); document.write( "(2y+5)^2+y^2=325
\n" ); document.write( "4y^2+20y+25+y^2=325
\n" ); document.write( "5y^2+20y+25-325=0
\n" ); document.write( "5y^2+20y-300=0
\n" ); document.write( "5(y^2+4y-60)=0
\n" ); document.write( "5(y-6)(y+10)=0
\n" ); document.write( "y-6=0
\n" ); document.write( "y=6 ans. x=2*6+5=12+5=17 ans.
\n" ); document.write( "y+10=0
\n" ); document.write( "y=-10 ans. x=2*-10+5=-20+5=-15 ans.
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\n" ); document.write( "17^2+6^2=325
\n" ); document.write( "289+36=325
\n" ); document.write( "325=325
\n" ); document.write( "-15^2-10^2=325
\n" ); document.write( "225+100=325
\n" ); document.write( "325=325
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