document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=271163>Question 271163</A>: <I><SPAN STYLE=\"word-break: break-all;\"> lf x, y, z are  consecutive odd integers and their sum is 27 . What is their  product  xyz?\r<BR>\n" );
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document.write( "A 720   b 693   c 990  d 1287  e 1485<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #198589 by </B><A HREF=/tutors/aboutme.mpl?userid=dabanfield><B>dabanfield(803)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dabanfield><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=198589\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> lf x, y, z are consecutive odd integers and their sum is 27 . What is their product xyz? <BR>\n" );
document.write( "A 720 b 693 c 990 d 1287 e 1485\r<BR>\n" );
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document.write( "Since the integers are consecutive and odd we know y = x+2 and z = x+4 so we have:\r<BR>\n" );
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document.write( "x + (x+2) + (x+4) = 27<BR>\n" );
document.write( "3x + 6 = 27<BR>\n" );
document.write( "3x = 21<BR>\n" );
document.write( "x = 7<BR>\n" );
document.write( "y = x+2 = 7+2 = 9<BR>\n" );
document.write( "z = x+4 = 7+4 = 11\r<BR>\n" );
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document.write( "The product then is 7*9*11 = ? </SPAN>\n" );
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